This question was previously asked in

SSC CHSL Previous Paper 109 (Held On: 21 Oct 2020 Shift 2)

- 15°
- 60°
- 30°
- 45°

Option 3 : 30°

**Calculation:**

sin(θ + 30°) = 3/√12

⇒ sin(θ + 30°) = 3/2√3 ----(√12 = 2√3)

⇒ sin(θ + 30°) = (3/2√3) × (√3/√3)

⇒ sin(θ + 30°) = (3/2√3) × (√3/√3)

⇒ sin(θ + 30°) = √3/2

⇒ sin(θ + 30°) = sin 60°

⇒ (θ + 30°) = 60°

⇒ θ = 30°

**The value of θ is equal to 30°**

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